CodeCharge TAIWAN

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#! /usr/bin/env python
# -*- coding: utf-8 -*-
# filename: exren.py
#
# 命令行批量重命名脚本
# this script intention batch rename files

def show_help():
    print """
    Extended renamer by realfun( http://2maomao.com/blog/ )
    
    Usage:
      exren [-x] pattern replace
    
    Options:
      -x: regular expression
      pattern: the target files that going to be renamed
      replace: the replace pattern (or regular expression replacer
    
    Notice:
      if you don't specify -x,
         the replace pattern should have the same count of * and ?
      if you specified -x,
         pattern string should grouped with ()
         replace string should looks like \\1, \\2 for each group in pattern string
    
    Examples:
      exren foo bar
      exren foo'*'.txt bar'*'.doc
      exren foo'?'.mp3 bar'?'.mp3
      exren -x (test\d+)\.mp3 \\1.mp3
"""

import os
from os import path
import sys
import re

def group_pattern(ptn):
    return ptn.replace('.', '\\.').replace('*', '(.*)').replace('?', '(.?)')

def group_replace(ptn):
    count = 1
    while re.search('[\*\?]', ptn):
        ptn = re.sub('[\*\?]', '\\\\' + str(count), ptn, 1)
        count += 1
    return ptn

def main():
    pattern = None
    replace = None
    if len(sys.argv) == 4 and sys.argv[1] == '-x':
        pattern = ARGV[2]
        replace = ARGV[3]
    elif len(sys.argv) == 3:
        pattern = group_pattern(sys.argv[1])
        replace = group_replace(sys.argv[2])
    else:
        show_help()
        return

    dir = os.getcwd()
    count = 0
    for file in os.listdir(dir):
        if re.match(pattern, file):
            count += 1
            new_file = re.sub(pattern, replace, file)
            print "  %s \t-> \t%s" % (file, new_file)
            cmd = 'mv "%s" "%s"' % (file, new_file)
            os.system(cmd)
    print
    print "== Renamed %d files ==" % count
    print

main()

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/Users/yehlu/exren.py '*'.JPG 2012-12-17'*'.JPG